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Problem-Solving and Data Analysis / Ratios, rates, proportional relationships, and units Difficulty: Hard

The density of a certain type of wood is 353  kilograms per cubic meter. A sample of this type of wood is in the shape of a cube and has a mass of 345 kilograms. To the nearest hundredth of a meter, what is the length of one edge of this sample? 

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Explanation

Choice B is correct. It’s given that the density of a certain type of wood is 353 kilograms per cubic meter kg/m3, and a sample of this type of wood has a mass of 345 kg. Let x represent the volume, in m3, of the sample. It follows that the relationship between the density, mass, and volume of this sample can be written
as 353 kg1 m3=345 kgx m3, or 353=345x. Multiplying both sides of this equation by x yields 353x=345. Dividing both sides of this equation by 353 yields x=345353. Therefore, the volume of this sample is 345353 m3. Since it’s given that the sample of this type of wood is a cube, it follows that the length of one edge of this sample can be found using the volume formula for a cube, V=s3, where V represents the volume, in m3, and s represents the length, in m, of one edge of the cube. Substituting 345353for V in this formula yields 345353=s3. Taking the cube root of both sides of this equation yields 3453533=s, or s0.99. Therefore, the length of one edge of this sample to the nearest hundredth of a meter is 0.99 .

Choices A, C, and D are incorrect and may result from conceptual or calculation errors.